# Line slope calculator 5x-3y=-15

**Straight line given by points A[0; 5] and B[3; 10]**

## Calculation:

**Slope-intercept form of line:**y = 1.6667x+5

**Canonical form of the line equation:**5x-3y+15 = 0

**Parametric form of the line equation:**

x = 3t

y = 5t+5 ; t ∈ R

**Slope:**m = 1.6667

**Slope angle of line: φ =**59°2'10″ = 1.0304 rad

**X intercept:**x

_{0}= -3

**Y intercept:**y

_{0}= q = 5

**Distance line from the origin:**d

_{0}= 2.5725

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(3; 5)

**Normal vector: n =**(5; -3)

**Midpoint of the segment AB: M =**[1.5; 7.5]

**Perpendicular Bisector equation:**3x+5y-42 = 0

**Vector OA = (0; 5) ; |OA| = 5**

**Vector OB = (3; 10) ; |OB| = 10.4403**

**Scalar product OA .OB = 50**

**Angle ∠ AOB = 16°41'57″ = 0.2915 rad**